Answer to Question #3275 in Differential Equations for mark kevin
y[sup]2[/sup] e[sup]2x[/sup] + log(3,y) = 2xln y
1
2011-07-01T10:59:58-0400
Clarify, please, your question.
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y^2 e^2x + log3 y = 2xln y
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