Question #327268

Solve the homogeneous differential equation š‘„š‘¦ š‘‘š‘¦/š‘‘š‘„ = š‘¦2 + š‘„2 š‘‘y/š‘‘š‘„   .

             


Expert's answer

xydydx=y2+x2dydxy=zxy′=z′x+zxzx(z′x+z)=z2x2+x2(z′x+z)zz′x+z2=z2+z′x+zz′(zāˆ’1)x=zzāˆ’1zdz=dxxzāˆ’ln⁔∣z∣+C′=ln⁔∣x∣yxāˆ’ln⁔∣y∣+ln⁔∣x∣+C′=ln⁔∣x∣yxāˆ’ln⁔∣y∣=Constxy\frac{dy}{dx}=y^2+x^2\frac{dy}{dx}\\y=zx\\y'=z'x+z\\xzx\left( z'x+z \right) =z^2x^2+x^2\left( z'x+z \right) \\zz'x+z^2=z^2+z'x+z\\z'\left( z-1 \right) x=z\\\frac{z-1}{z}dz=\frac{dx}{x}\\z-\ln \left| z \right|+C'=\ln \left| x \right|\\\frac{y}{x}-\ln \left| y \right|+\ln \left| x \right|+C'=\ln \left| x \right|\\\frac{y}{x}-\ln \left| y \right|=Const


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