Question #318191

Solve the initial value problem.


y′′+y=1, y(0)=2, y′(0)=7.


1
Expert's answer
2022-03-29T11:47:45-0400

y+(y1)=0(y1)+(y1)=0λ2+1=0λ=±iy1=C1cost+C2sinty=1+C1cost+C2sint{y(0)=2y(0)=7{1+C1=2C2=7{C1=1C2=7y=1+7cost+sinty''+\left( y-1 \right) =0\\\left( y-1 \right) ''+\left( y-1 \right) =0\\\lambda ^2+1=0\Rightarrow \lambda =\pm i\\y-1=C_1\cos t+C_2\sin t\\y=1+C_1\cos t+C_2\sin t\\\left\{ \begin{array}{c} y\left( 0 \right) =2\\ y'\left( 0 \right) =7\\\end{array} \right. \Rightarrow \left\{ \begin{array}{c} 1+C_1=2\\ C_2=7\\\end{array} \right. \Rightarrow \left\{ \begin{array}{c} C_1=1\\ C_2=7\\\end{array} \right. \\y=1+7\cos t+\sin t


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