Question #315713

dy/dx= y(xy^(5) − 1)

Expert's answer

y’=y(xy5−1)=xy6−yy’=y(xy^5-1)=xy^6-y

z=y−5z=y^{-5}

y’=−15z−65z’y’=-\frac15z^{-\frac65}z’

−15z−65z’=xz−65−z−15-\frac15z^{-\frac65}z’=x z^{-\frac65}-z^{-\frac15}

z’−5z=−5xz’-5z=-5x

z=uvz=uv

u’v+uv’−5uv=−5xu’v+uv’-5uv=-5x

u’v+u(v’−5v)=−5xu’v+u(v’-5v)=-5x

v’−5v=0v’-5v=0

v=e5xv=e^{5x}

u’e5x=−5xu’e^{5x}=-5x

u=−∫5xe−5xdx=15e−5x(5x+1)+Cu=-\int 5xe^{-5x}dx=\frac15e^{-5x}(5x+1)+C

z=uv=x+15+Ce5x=y−5z=uv=x+\frac15+Ce^{5x}=y^{-5}

y=(x+15+Ce5x)−15y=(x+\frac15+Ce^{5x})^{-\frac15}

Answer: y=(x+15+Ce5x)−15y=(x+\frac15+Ce^{5x})^{-\frac15}.


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