Question #314507

Find the general solution of the equation:


𝑥^2𝑦" − 9𝑥𝑦′ + 25𝑦 = 0

1
Expert's answer
2022-03-20T13:20:31-0400

x=eux=e^u

a0λ(λ1)(λ2)...(λn+2)...+an2λ(λ1)+an1λ+an=0a_0\lambda(\lambda-1)(\lambda-2)...(\lambda-n+2)...+a_{n-2}\lambda(\lambda-1)+a_{n-1}\lambda+a_n=0

(λ1)λ9λ+25=0(\lambda-1)\lambda-9\lambda+25=0

λ210λ+25=0\lambda^2-10\lambda+25=0

λ1,2=5\lambda_{1,2}=5

k=2

y=(C1u+C)e5uy=(C_1u+C)e^{5u}

y=C1x5ln(x)+Cx5y=C_1x^5ln(x)+Cx^5


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