Question #312174

solve the D.E dy/dx = (6x^5-2x+1)/(cosy+e^y)


1
Expert's answer
2022-03-16T11:39:59-0400

dydx=6x52x+1cosy+ey(cosy+ey)dy=(6x52x+1)dx(cosy+ey)dy=(6x52x+1)dxsiny+ey=x6x2+x+C.\frac{dy}{dx}=\frac{6x^5-2x+1}{\cos y +e^y}\\ (\cos y +e^y)dy=(6x^5-2x+1)dx\\ \int(\cos y +e^y)dy=\int(6x^5-2x+1)dx\\ \sin y+e^y=x^6-x^2+x+C.


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