Find a function y of x such that
9yy'=x and y(9)=10
The equation "9yy'=x" is equivalent to "9ydy=xdx." It follows that "\\int 9ydy=\\int xdx," and hence the general solution is "\\frac{9}2y^2=\\frac{1}2x^2+C" which is equivalent to "9y^2=x^2+C."
Since "y(9)=10," we get that "9\\cdot 10^2=9^2+C," and hence "C=819."
We conclude that the particular solution is "9y^2=x^2+819."
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