Question #305390

Under a certain condition , cane sugar in water is converted into dextrose at a rate proportional to the amount that is unconverted at any time . If 75 kg at t =; 0, 8 kg are converted during the first 30 minutes , find the amount converted in 2 hours .

1
Expert's answer
2022-03-07T17:26:05-0500

Let m0=75kgm_0 = 75kg be the initial mass of the shugar, mm - is the amount of converted sugar. Thus, the differential equation of the process will be:


dmdt=r(m0m)\dfrac{dm}{dt} = r(m_0-m)

where rr is the coefficient of proportionality. Solving the euqiation, obtain:


m=m0(1ert)m = m_0(1 - e^{-rt})

Since m=8kgm = 8kg at t=0.5hrst = 0.5hrs, obtain the coeffitient rr:


r=1tln(1mm0)=10.5hrsln(18kg75kg)0.23hrs1r = -\dfrac{1}{t}\ln(1-\dfrac{m}{m_0} ) = -\dfrac{1}{0.5hrs}\ln(1-\dfrac{8kg}{75kg} ) \approx 0.23hrs^{-1}

At t=2hrst = 2hrs obtain:


m=75kg(1e0.23hrs12hrs)48kgm = 75kg\cdot (1-e^{-0.23hrs^{-1}\cdot 2hrs})\approx 48kg

Answer. 48kg.


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