Question #305014

Non-Exact Differential Equations. Find the complete solution of ydx + (x + y ^ 2) dy = 0

1
Expert's answer
2022-03-04T05:53:41-0500
ydx+(x+y2)dy=0ydx+(x+y^2)dy=0

dxdy+1yx=y\dfrac{dx}{dy}+\dfrac{1}{y}x=-y

I.F.=e(1/y)dy=yI.F.=e^{\int(1/y)dy}=y

ydx+xdy=y2dyydx+xdy=-y^2dy

d(xy)=y2dyd(xy)=-y^2dy

Integrate


d(xy)=y2dy\int d(xy)=-\int y^2dy

xy=y33+Cxy=-\dfrac{y^3}{3}+C

xy+y33=Cxy+\dfrac{y^3}{3}=C


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