Solution of differential equation p^ 2 +5p+6=0 is...
Solution
If p = du/dx solving given equation we will get "p_{1,2}=-2.5\\pm\\sqrt{{2.5}^2-6}=-2.5\\pm0.5"
So given differential equation may be rewritten in the form
(du/dx + 2)( du/dx + 3)=0
du1/dx=-2 and du2/dx = -3 => u1 = -2x + C, u2 = -3x + D
So given differential equation has two solutions (C and D are arbitrary constants)
u1(x) = -2x + C
u2(x) = -3x + D
Comments
Leave a comment