Question #301370

a curve is such that d²y/dx²=12x-12. find the equation at point (2,9)?


1
Expert's answer
2022-02-25T12:37:34-0500
dydx=(12x12)dx=6x212x+C1\dfrac{dy}{dx}=\int(12x-12)dx=6x^2-12x+C_1

y=(6x212x+C1)dx=2x36x2+C1x+C2y=\int(6x^2-12x+C_1)dx=2x^3-6x^2+C_1 x+C_2

Point (2,9)(2,9)


9=2(2)36(2)2+2C1+C29=2(2)^3-6(2)^2+2C_1+C_2

C2=172C1C_2=17-2C_1

The equation of the curve is


y=2x36x2+Cx+172Cy=2x^3-6x^2+C x+17-2C

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