Find the Solution of
(D^3-3D^2-3D+1)y=0
Solution
It is a linear homogeneous equation. The characteristic equation is
λ3 - 3λ2 - 3λ + 1=0 => λ3 + 1 - 3 λ (λ + 1) = 0 => (λ + 1) (λ2 - λ + 1) - 3 λ (λ + 1) = 0 =>
(λ + 1) (λ2 - 4λ + 1) = 0
So there are three roots of the characteristic equation
"\\lambda_1=-1,{\\ \\lambda}_2=2-\\sqrt3,\\ \\lambda_3=2+\\sqrt3"
Therefore the solution of given equation is
"y(x)=C_1e^{-x}+C_2e^{(2-\\sqrt3)x}+C_3e^{(2+\\sqrt3)x}"
where C1, C2, C3 are arbitrary constants.
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