Question #290236

Find the general solution to the differential equation 4d^2y/dx^2+4dy/dx+y=0

1
Expert's answer
2022-01-25T06:07:03-0500

Charasteristic equation:

4k2+4k+1=04{k^2} + 4k + 1 = 0

D=1616=0D = 16 - 16 = 0

k=48=12k = \frac{{ - 4}}{8} = - \frac{1}{2}

Then

y=C1ekx+xC2ekx=C1e12x+xC2e12xy = {C_1}{e^{kx}} + x{C_2}{e^{kx}} = {C_1}{e^{ - \frac{1}{2}x}} + x{C_2}{e^{ - \frac{1}{2}x}}

Answer: y=C1e12x+xC2e12xy = {C_1}{e^{ - \frac{1}{2}x}} + x{C_2}{e^{ - \frac{1}{2}x}}


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