a) Establish the relation π
π
ππ₯
π
(π₯
2 β 1)
π = π! 2
π ππ(π₯)
b) Use Laplace transform to solve
π
2π¦
ππ‘
2 + 2
ππ¦
ππ‘ + π¦ = π‘π
βπ‘ π€ππ‘β π¦(0) = 1, π¦
β²
(0) = β2
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