Question #281401

F or the follow ing differential equation locate and classify its singular points on the x-axis


π‘₯²𝑦′′+ (2βˆ’π‘₯)𝑦′= 0.

1
Expert's answer
2021-12-21T17:46:06-0500

yβ€²β€²+2βˆ’xx2yβ€²=0y''+\frac{2-x}{x^2}y'=0


P(x)=2βˆ’xx2P(x)=\frac{2-x}{x^2}


x = 0 is singular point

(xβˆ’0)P(x)=2βˆ’xx(x-0)P(x)=\frac{2-x}{x} is not analytic at x = 0

so, x = 0 is irregular singular point


x = 2 is singular point

(xβˆ’2)P(x)=βˆ’(xβˆ’2)2x2(x-2)P(x)=-\frac{(x-2)^2}{x^2} ​is analytic at x = 2

so, x = 2 is regular singular point


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