Answer to Question #281315 in Differential Equations for Piyali

Question

1) dx/dy+4y=12 for y(0)=1 (general nad particular solution)

Answer 1

$\displaystyle \frac{dx}{dy}=12-4y\\ dx= dy(12-4y)\\ x = 12y - 2y^2\\ \implies 12y -2y^2-x =0\\ y(0) =1\\ \implies 12-2-x =0\\ x=10\\ \text{The general solution is given by}\\ 12y -2y^2-10=0$