Differential equation of a LR circuit
Rq′+Cq=UGiven U=110V,R=3000 Ohm,C=5×10−6 F
Substitute
3000q′+200000q=110q′+3200q=0.11 Integrating factor
μ(t)=e∫(200/3)dt=e(200/3)t
e(200/3)t(q′+3200q)=0.11e(200/3)t
d(e(200/3)tq)=0.11e(200/3)tdt Integrate
∫d(e(200/3)tq)=∫0.11e(200/3)tdt
e(200/3)tq=0.00165e(200/3)t+C
q(t)=1.65×10−3+Ce−(200/3)t q(0)=50×10−6A
0.05×10−3=1.65×10−3+C
C=−1.60×10−3
q(t)=1.65×10−3−1.60×10−3e−(200/3)t
q(0.05)=1.65×10−3−1.60×10−3e−(200/3)(0.05)
q(0.05)=1.593 mC
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