Question #279737

Find a general solution of (4D^2+4D+17)y= 0

1
Expert's answer
2021-12-15T12:24:58-0500

The auxiliary equation is

4m2+4m+17=04m^2+4m+17=0

m=4±16688m = \dfrac{-4 \pm \sqrt{16-68}}{8}

m=2±13i4m = \dfrac{-2 \pm \sqrt{13}i}{4}

The general solution of the differential equation is

y=e12t[Acos(134t)+iBsin(134t)]y = e^{-\frac{1}{2}t}[A\cos( \frac{\sqrt{13}}{4}t) + iB \sin( \frac{\sqrt{13}}{4}t)]






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