Find a general solution of (4D^2+4D+17)y= 0
The auxiliary equation is
4m2+4m+17=04m^2+4m+17=04m2+4m+17=0
m=−4±16−688m = \dfrac{-4 \pm \sqrt{16-68}}{8}m=8−4±16−68
m=−2±13i4m = \dfrac{-2 \pm \sqrt{13}i}{4}m=4−2±13i
The general solution of the differential equation is
y=e−12t[Acos(134t)+iBsin(134t)]y = e^{-\frac{1}{2}t}[A\cos( \frac{\sqrt{13}}{4}t) + iB \sin( \frac{\sqrt{13}}{4}t)]y=e−21t[Acos(413t)+iBsin(413t)]
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