A circuit has in series an electromotive force given by E=40-sin35tV, a resistor of 10Ω, and an inductor of 0.4H . If the initial current is 2 , find the current at time t>2.
XL=wL=35⋅0.4=14 ΩX_L = wL =35\cdot0.4= 14\ ΩXL=wL=35⋅0.4=14 Ω
Z=R+jwL=10+j14 ΩZ = R + jwL = 10 + j14\ ΩZ=R+jwL=10+j14 Ω
The magnitude of Z:
Z=R2+(wL)2=102+142=17.20 ΩZ = \sqrt{R^2 + (wL)^2} = \sqrt{10^2 +14^2} = 17.20\ ΩZ=R2+(wL)2=102+142=17.20 Ω
The phase angle of Z:
φ=tan−1(wL/R)=tan−1(14/10)=54°=0.94\varphi = tan^{-1} ( wL/R) = tan^{-1} (14/10) = 54°=0.94φ=tan−1(wL/R)=tan−1(14/10)=54°=0.94 rad
current:
I(t)=2sin(35t−0.94)I(t)=2sin(35t-0.94)I(t)=2sin(35t−0.94)
I(2)=2sin(70−0.94)=−0.11I(2)=2sin(70-0.94)=-0.11I(2)=2sin(70−0.94)=−0.11 A
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