Question #275178

y''-10y'+25y=0 find general solution of the given second order differential equation.


1
Expert's answer
2021-12-06T11:17:18-0500

Let us consider DE

y10y+25y=0y''-10y'+25y=0

The characteristic equation is given by

k210k+25=0k^2-10k+25=0

Roots:

k1=5,k2=5k_1=5,\quad k_2=5

General solution

y(x)=C1e5x+C2xe5xy(x)=C_1e^{5x}+C_2xe^{5x}


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