Question #273943

A metal bar at a temperature of 100 deg. fahrenheit is placed in a room at a constant temperature of 0 deg. fahrenheit. If after 20 minutes the temperature of the bar is 50 deg. Fahrenheit, find: a) the time it will take the bar to reach a temperature of 25 deg. Fahrenheit? b) the temperature of the bar after 10 minutes?

1
Expert's answer
2021-12-02T06:55:43-0500

a) the time it will take the bar to reach a temperature of 25 deg. Fahrenheit?

We can use Newton's Law of Cooling: The temperature T of an object with initial temperature T0T_0 after tt minutes in a room with ambient temperature TrT_r   is given by:

T=Cekt+TrT=Ce^{-kt}+T_r

Here  Tr=0T_r=0 . We are given points (t,T)(t,T)  as (0,100)(0,100) and (20,50)(20,50)

100=Ce0×t    C=100100=Ce^{0\times t}\implies C=100

50=100e20k    k=ln(0.5)200.03550=100e^{-20k} \implies k={ln(0.5)\over -20}\approx 0.035

    T=100e0.035t\implies T=100e^{-0.035t}

To get the time it will take the bar to reach a temperature of 25 deg. Fahrenheit

T=100e0.035tT=100e^{-0.035t}

25=100e0.035t25=100e^{-0.035t}

e0.035t=25100e^{-0.035t}={25\over 100}

ln(e0.035t)=ln(25100)ln(e^{-0.035t})=ln({25\over 100})

0.035t=ln(25100)    t=ln(25100)0.035=39.6-0.035t=ln({25\over 100})\implies t={ln({25\over 100})\over -0.035}=39.6 minutes

b) To get the temperature of the bar after 10 minutes

T=100e0.035×10=70.5°FT=100e^{-0.035\times 10}=70.5\degree F


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