Solve the equation in exact differentials: (3x2+2y)dx+(2x-3)dy=0
"(3x^2+2y)_y=(2x-3)_x=2"
"F=\\int (3x^2+2y)dx=x^3+2xy+g(y)"
"F_y=2x+g'(y)=2x-3"
"g'(y)=-3"
"g(y)=-3y+c"
"F=x^3+2xy-3y+c"
"x^3+2xy-3y+c=0"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment