Question #271005

Find the linear substitution that reduces the inhomogeneous equation to the homogeneous one: y,=x+y-3/y-x+1


1
Expert's answer
2021-11-29T17:07:24-0500

A first order differential equation

dy/dx=f(x,y)dy/dx=f(x,y)

is called homogeneous equation, if the right side satisfies the condition

f(tx,ty)=f(x,y)f(tx,ty)=f(x,y)


we have:

f(x,y)=x+y3yx+1f(x,y)=x+\frac{y-3}{y-x}+1

then:

f(tx,ty)=tx+ty3tytx+1f(tx,ty)=tx+\frac{ty-3}{ty-tx}+1


x+y3yx+1=tx+ty3tytx+1x+\frac{y-3}{y-x}+1=tx+\frac{ty-3}{ty-tx}+1


x(yx)+y3=t2x(yx)+ty3x(y-x)+y-3=t^2x(y-x)+ty-3

x(yx)(t21)+y(t1)=0x(y-x)(t^2-1)+y(t-1)=0

x(yx)(t+1)+y=0x(y-x)(t+1)+y=0


t=yx(yx)1t=-\frac{y}{x(y-x)}-1


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