Find inverse laplace transform
(2s-56)/(s^2-4s-12)
"\\frac{2s-56}{s^2-4s-12}=\\frac{2s-56}{(s+2)(s-6)}=\\frac{15}{2(s+2)}-\\frac{11}{2(s-6)}"
"L^{-1}(\\frac{15}{2(s+2)}-\\frac{11}{2(s-6)})=\\frac{15}{2}e^{-2t}-\\frac{11}{2}e^{6t}."
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