Question #263434

Determine the general solution to the equation ∂2u/∂t2=c2(∂2u/∂x2) under the boundary conditions u(0,t)=u(1,t)=0 and initial conditions u(x,0)=Φ(x), ut(x,o)=Ψ(x)


1
Expert's answer
2021-11-17T10:09:47-0500

solution of the one-dimensional wave equation:

u(x,t)=Ansin(πnx/l)cos(πnct/l)u(x,t)=\sum A_nsin(\pi nx/l)cos(\pi nct/l)

where

An=2l0lu(x,0)sin(πnx/l)dx=2l0lΦ(x)sin(πnx/l)dxA_n=\frac{2}{l}\int^l_0 u(x,0)sin(\pi nx/l)dx=\frac{2}{l}\int^l_0 \Phi (x)sin(\pi nx/l)dx


then:

ut(x,t)=Anπclsin(πx/l)sin(πct/l)u_t(x,t)=-\frac{A_n\pi c}{l}sin(\pi x/l)sin(\pi ct/l)

ut(x,0)=Ψ(x)=0u_t(x,0)=Ψ(x)=0


l is length of object where wave occurs (for example, string)


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