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Answer to Question #261822 in Differential Equations for blossomqt
Question #261822
Β π₯2π¦=1+ππ₯
Expert's answer
differentiate both parts of the given equation respect to x:
"(\ud835\udc65^2\ud835\udc66)_x'=(1+\ud835\udc50\ud835\udc65)_x'"
we can get Differential Equation:
"2xy+x^2y'=c"
Learn more about our help with Assignments: Differential Equations
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