Question #261822

 𝑥2𝑦=1+𝑐𝑥


1
Expert's answer
2021-11-09T16:49:36-0500

differentiate both parts of the given equation respect to x:

(𝑥2𝑦)x=(1+𝑐𝑥)x(𝑥^2𝑦)_x'=(1+𝑐𝑥)_x'


we can get Differential Equation:

2xy+x2y=c2xy+x^2y'=c


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