Question

𝑦𝑠𝑖𝑛(𝑥) − 𝑥𝑦2 = 𝑐

Answer 1

differentiate both parts of the given equation respect to x:

$(𝑦𝑠𝑖𝑛(𝑥) − 𝑥𝑦^2)_x' =( 𝑐)_x'$

we can get Differential Equation:

$y'sinx+ycosx-y^2-2yy'x=0$