Question #240179

Given that p(x) = x is a particular solution to the

differential equation y''+ y = x write the generalized sotlution and check by verifying that the solution satisfies

the equation


1
Expert's answer
2021-09-22T22:55:43-0400

Let us solve the differential equation y+y=x.y''+ y = x. The characteristic equation k2+1=0k^2+1=0 has the roots k1=ik_1=i and k2=i.k_2=-i. Taking into account that p(x)=xp(x) = x is a particular solution, we conclude that the general solution is y=C1cosx+C2sinx+x.y=C_1\cos x+C_2\sin x+x.

Let us show that the solution satisfies the equation. Since y=C1sinx+C2cosx+1, y=C1cosxC2sinx,y'=-C_1\sin x+C_2\cos x+1,\ y''=-C_1\cos x-C_2\sin x, and

y+y=C1cosxC2sinx+C1cosx+C2sinx+x=x,y''+ y=-C_1\cos x-C_2\sin x+C_1\cos x+C_2\sin x+x=x,

we conclude that y=C1cosx+C2sinx+xy=C_1\cos x+C_2\sin x+x is indeed the solution of the equation.


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