Question #23963

Consider the equation yu_x - xu_y = 0, (y>0). Check for each of the following initial conditions whether the problem is solvable. If it is solvable, find a solution. If it is not, explain why:

a) u(x,0) = x^2
b) u(x,0) = x
c) u(x,0) = x, x>0

Expert's answer

Conditions

Consider the equation yu_xxu_y=0yu\_x - xu\_y = 0, (ygt;0)(y\>gt;0). Check for each of the following initial conditions whether the problem is solvable. If it is solvable, find a solution. If it is not, explain why:

a) u(x,0)=x2u(x,0) = x^2

b) u(x,0)=xu(x,0) = x

c) u(x,0)=x,xgt;0u(x,0) = x, x\>gt;0

Solution

ydudxxdudy=0y \frac{du}{dx} - x \frac{du}{dy} = 0dxy=dyx=du0\frac{dx}{y} = \frac{dy}{x} = \frac{du}{0}φ1(x,y,u)=u\varphi_1(x,y,u) = udxy=dyx\frac{dx}{y} = \frac{dy}{x}x2y2=cx^2 - y^2 = cΦ(u,x2y2)=0\Phi(u, x^2 - y^2) = 0u=f(x2y2)u = f(x^2 - y^2)


Where ff has a derivative at some interval.

So we can see now, that the problem is solvable for 1st1^{st} condition.

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