The integral curves of dxa=dyb=dz\frac {dx}{a} = \frac {dy}{b} = dzadx=bdy=dz is
Let's consider dxa=dyb.\frac{dx}{a}= \frac{dy}{b}.adx=bdy. Antiderivatives are related by the folowing equalitie xa=yb+c1\frac{x}{a}=\frac{y}{b}+c_1ax=by+c1 .
Let's consider the dxa=dz\frac{dx}{a}= dzadx=dz . Antiderivatives are related by the folowing equalitie xa=z+c2.\frac{x}{a}=z+c_2.ax=z+c2.
So the answer is xa=y+c1bb=z+c2\frac{x}{a}=\frac{y+c_1b}{b}=z+c_2ax=by+c1b=z+c2
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