Using the method of undetermined co-efficients we find the particular solution to thegiven differential equation.Let yp represent the particualar solution. ∴yp=Aet where A is a constant⟹yp′=Aet,yp′′=AetSubstituting into the given differential equation we have thatAet−4Aet+4Aet=et⟹Aet=et∴A=1Hence, et is a solution to the given differential equation.
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