Question #236354
Obtain a family of solutions for the homogeneous differential equation
1
Expert's answer
2021-09-12T23:52:49-0400

a)


y8y+12y=0y''-8y'+12y=0

Auxiliary (characteristic) equation


r28r+12=0r^2-8r+12=0

(r2)(r6)=0(r-2)(r-6)=0

r1=2,r2=6r_1=2, r_2=6

The family of solutions of the given differemtial equation is


y=C1e2t+C2e6ty=C_1e^{2t}+C_2e^{6t}

b)


y+10y+25y=0y''+10y'+25y=0

Auxiliary (characteristic) equation


r2+10r+25=0r^2+10r+25=0

(r+5)2=0(r+5)^2=0

r1=r2=5r_1=r_2=-5

The family of solutions of the given differemtial equation is


y=C1e5t+C2te5ty=C_1e^{-5t}+C_2te^{-5t}

c)


y8y+65y=0y''-8y'+65y=0

Auxiliary (characteristic) equation


r28r+65=0r^2-8r+65=0

D=(8)24(1)(65)=196<0D=(-8)^2-4(1)(65)=-196<0

r1,2=8±1962(1)=4±7ir_{1,2}=\dfrac{8\pm\sqrt{-196}}{2(1)}=4\pm7i

The family of solutions of the given differemtial equation is


y=C1e4tcos(7t)+C2e4tsin(7t)y=C_1e^{4t}\cos(7t)+C_2e^{4t}\sin(7t)


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