Question #236140

what is the differential equation having a solution y=cx²+cx?


Expert's answer

Consider the solution y=cx+cx2y=cx+cx^2

Require to find the differential equation from the given solution.

To find the differential equation, let us eliminate the parameter cc by differentiating the given equation with respect to xx

Differentiating the given equation y=cx+cx2y=cx+cx^2 with respect to x , we get

y=c(1)+c(2x)y'=c(1)+c(2x)

Implies, we get y=c+2cxy'=c+2cx

Implies, we get y=c(1+2x)y'=c(1+2x)

c=y1+2x\Rightarrow c=\frac{y'}{1+2x}

Substituting the value of cc in the given equation y=cx+cx2y=cx+cx^2 , we get

y=x[y1+2x]+x2[y1+2x]\Rightarrow y=x[\frac{y'}{1+2x}]+x^2[\frac{y'}{1+2x}]

y(1+2x)=xy+x2y\Rightarrow y(1+2x)=xy'+x^2y'

y(1+2x)=y(x+x2)\Rightarrow y(1+2x)=y'(x+x^2)

Therefore, the required differential equation is

y=y(1+2x)(x+x2)y'=\frac{y(1+2x)}{(x+x^2)}



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