Question #235138
In x dx/dy=2/xy^3
1
Expert's answer
2021-09-14T06:08:42-0400

Given (lnx)dxdy=2xy3(ln x) \frac{dx}{dy}=\frac{2}{xy^3}

It can be written as,


(xlnx)dx=2y3dy(xln x){dx}=\frac{2}{y^3}dy


2y3dy=(xlnx)dx\frac{2}{y^3}dy = (xln x){dx}


Integrating both sides,

1y2=[12x2ln(x)x24]+C-\frac{1}{y^2}=[\frac{1}{2}x^2\ln \left(x\right)-\frac{x^2}{4}] + C






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