Question

Find the general/particular solution of the following Differential Equations

(Non-Exact D.E)

(t² + 1) dI - (t-It) dt=0

Answer 1

$\frac{t}{t^2+1}dt=\frac{1}{1-l}dl$

$\frac{ln(t^2+1)}{2}=lnc_1-ln(l-1)$

$(t^2+1)(l-1)^2=c$