Question #232788

(e^2x + 4) dy/dx = y


1
Expert's answer
2021-09-10T00:09:47-0400

dxe2x+4=dyy\frac{dx}{e^{2x}+4}=\frac{dy}{y}

Letz=e2x+4Let z=e^{2x}+4

dz=2e2xdx=2(z4)dxdz=2e^{2x}dx=2(z-4)dx

dx=dz2(z4)dx=\frac{dz}{2(z-4)}

dyy=dxz=dz2z(z4)=1/8(1z41z)dz\frac{dy}{y}=\frac{dx}{z}=\frac{dz}{2z(z-4)}=1/8(\frac{1}{z-4}-\frac{1}{z})dz

lny=1/8(ln(z4)lnz)+Clny=1/8(ln(z-4)-lnz)+C

lny=1/8(2xln(e2x+4))+Clny=1/8(2x-ln(e^{2x}+4))+C




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS