Question #230931

Find all solutions of the given differential equations and then find the particular solutions for which a point (x,y) is given:


dy/dx = -32x + 8 ; (x,y) = (0,1)


1
Expert's answer
2021-09-03T02:40:59-0400
dydx=32x+8\dfrac{dy}{dx}=-32x+8

dy=(32x+8)dxdy=(-32x+8)dx

Integrate


dy=(32x+8)dx\int dy=\int(-32x+8)dx

y=16x2+8x+Cy=-16x^2+8x+C

The general solution of the given differential equation is


y(x)=16x2+8x+Cy(x)=-16x^2+8x+C



Point (x,y)=(0,1)(x,y)=(0,1)


1=16(0)2+8(0)+C=>C=11=-16(0)^2+8(0)+C=>C=1

The particular solution is


y=16x2+8x+1y=-16x^2+8x+1


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