Question #230760

what function do you know from calculus is such that its first derivative is itself? Its first derivative is a constant multiple k of itself? Write each answer in the form of a first-order differential equation with a solution.


1
Expert's answer
2021-08-30T16:34:33-0400

1.


dydx=y\dfrac{dy}{dx}=y

dyy=dx\dfrac{dy}{y}=dx

Integrate


dyy=dx\int\dfrac{dy}{y}=\int dx

lny=x+lnC\ln|y|=x+\ln C

y=Cexy=Ce^x


2.


dydx=ky\dfrac{dy}{dx}=ky

dyy=kdx\dfrac{dy}{y}=kdx

Integrate


dyy=kdx\int\dfrac{dy}{y}=\int kdx

lny=kx+lnC\ln|y|=kx+\ln C

y=Cekxy=Ce^{kx}


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