Find the solution of the given differential equation and then find the particular solution for which a point (x,y) is given:
dy/dx = (3x - 4)
dydx=3x−4dy=(3x−4)dxIntegrating both side, we gety=32x2−4x+cThis is the required general solution.To find particular solution we need one initial condition.\frac{dy}{dx}=3x-4\\ dy=(3x-4)dx\\ \text{Integrating both side, we get}\\ y=\frac{3}{2}x^2-4x+c\\ \text{This is the required general solution.}\\ \text{To find particular solution we need one initial condition.}dxdy=3x−4dy=(3x−4)dxIntegrating both side, we gety=23x2−4x+cThis is the required general solution.To find particular solution we need one initial condition.
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