Question #225567

1. Show whether or not the following differential equations are separable:

1.1 dydx=x+1y1\frac{dy}{dx}=\frac{x+1}{y-1}


1.2 dydx=yex+yx2+2\frac{dy}{dx}=\frac{ye^{x}+y}{x^2+2}



1.3 dsdt=tln(s2t)+8t2\frac{ds}{dt}=t\ln(s^{2t})+8t^2


1
Expert's answer
2021-08-13T08:15:14-0400

1.1


dydx=x+1y1\dfrac{dy}{dx}=\dfrac{x+1}{y-1}

(y1)dy=(x+1)dx(y-1)dy=(x+1)dx

The equation is separable.


1.2


dydx=yex+yx2+2\dfrac{dy}{dx}=\dfrac{ye^x+y}{x^2+2}

dydx=y(ex+1x2+2)\dfrac{dy}{dx}=y(\dfrac{e^x+1}{x^2+2})

1ydy=(ex+1x2+2)dx\dfrac{1}{y}dy=(\dfrac{e^x+1}{x^2+2})dx

The equation is separable.


1.3


dsdt=tln(s2t)+8t2\dfrac{ds}{dt}=t\ln(s^{2t})+8t^2

dsdt=t(2t)ln(s)+8t2\dfrac{ds}{dt}=t(2t)\ln(s)+8t^2

dsdt=2t2(ln(s)+4)\dfrac{ds}{dt}=2t^2(\ln(s)+4)




dsln(s)+4=2t2dt\dfrac{ds}{\ln(s)+4}=2t^2dt

The equation is separable.



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