Question #223115

Find the general solution of these differential equations.

7) ydy/dx =1/ √(x) 8) dy/dx = 4x√(1-y2) 9) dy/dx = x(4+y2)




1
Expert's answer
2021-09-16T00:46:51-0400

Let us find the general solution of these differential equations.


7) Let us solve the equation ydydx=1xy\frac{dy}{dx} =\frac{1}{\sqrt{x}} which is equivalent to ydy=dxx.ydy =\frac{dx}{\sqrt{x}}. It follows that ydy=dxx,\int ydy =\int\frac{dx}{\sqrt{x}}, and we conclude that the general solution is y22=2x+C.\frac{y^2}2=2\sqrt{x}+C.


8) Let us solve the equation dydx=4x1y2\frac{dy}{dx} = 4x\sqrt{1-y^2} which is equivalent to dy1y2=4xdx.\frac{dy}{\sqrt{1-y^2}} = 4xdx. It follows that dy1y2=4xdx,\int\frac{dy}{\sqrt{1-y^2}} = 4\int xdx, and therefore, the general solution is arcsiny=2x2+C.\arcsin y=2x^2+C.


9) Let us solve the equation dydx=x(4+y2)\frac{dy}{dx} = x(4+y^2) which is equivalent to dy4+y2=xdx.\frac{dy}{4+y^2} = xdx. It follows that dy4+y2=xdx,\int\frac{dy}{4+y^2} = \int xdx, and we conclude that the general solution is 12arctany2=x22+C.\frac{1}2\arctan \frac{y}2=\frac{x^2}2+C.



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