Let us find the general solution of these differential equations.
7) Let us solve the equation ydxdy=x1 which is equivalent to ydy=xdx. It follows that ∫ydy=∫xdx, and we conclude that the general solution is 2y2=2x+C.
8) Let us solve the equation dxdy=4x1−y2 which is equivalent to 1−y2dy=4xdx. It follows that ∫1−y2dy=4∫xdx, and therefore, the general solution is arcsiny=2x2+C.
9) Let us solve the equation dxdy=x(4+y2) which is equivalent to 4+y2dy=xdx. It follows that ∫4+y2dy=∫xdx, and we conclude that the general solution is 21arctan2y=2x2+C.
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