Determine the differential equation arising from y=c1e5x+c2e7x
Given the the solution y=c1e5x+c2e7x, we know thatk1=5 and k2=7The complimentary solution is(k−5)(k−7)=0=k2−12k+35=0Therefore the differential equation isy′′−12y′+35y=0\text{Given the the solution $y=c_1e^{5x}+c_2e^{7x}$, we know that}\\\text{$k_1=5$ and $k_2=7$} \\\text{The complimentary solution is}\\(k-5)(k-7)=0\\=k^2-12k+35=0 \\\text{Therefore the differential equation is}\\y''-12y'+35y=0Given the the solution y=c1e5x+c2e7x, we know thatk1=5 and k2=7The complimentary solution is(k−5)(k−7)=0=k2−12k+35=0Therefore the differential equation isy′′−12y′+35y=0
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