Solution;
F(p,q)=p+q-pq=0
Let the complete integral of F(a,b) be given as;
In which p=a,q=b
z=ax+by+c.....(i)
Using our equation;
F(a,b)=a+b-ab=0
Solve for a;
a+b(1-a)=0
b=aa−1\frac{a}{a-1}a−1a
Which can be substituted back in the equation (i)
z=ax+aa−1\frac{a}{a-1}a−1ay+c
Answer;
z=ax+aa−1y+cax+\frac{a}{a-1}y+cax+a−1ay+c
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