The Z-transform of following function will be
Z[n(n−1)(n−2)]=Z[n(n2−3n+2)]=Z[n3−3n2+2n]
=Z[n3]−3Z[n2]+2Z[n]
= We know that Z transform of n3 is given by
Z[n3]=(z−1)4z3+4z2+z
Z[n2]=(z−1)3z2+z
Z[n]=(z−1)2z
Now putting these values in above equation , we get
= (z−1)4z3+4z2+z+(z−1)3z2+z+(z−1)2z
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