Question

dx/y+1 =dy/X+1=dz/z

Answer 1

$\int(x+1)dx=\int(y+1)dy$

$x^2/2+x=y^2/2+y+c_1$

$\frac{dx-dy}{y-x}=\frac{dz}{z}$

$-ln(x-y)=lnz+lnc_2$

$\frac{1}{x-y}=c_2z$

$F(x^2/2+x-y^2/2-y,\frac{1}{z(x-y)})=0$