Answer to Question #195963 in Differential Equations for Saugat Adhikari

Question #195963

For any X and suitable p and q, solve y=Xpqz for z


*** Y=Xpq to the power z


1
Expert's answer
2021-05-21T11:05:52-0400

If "q=\\frac{\\partial z}{\\partial y}=0" , then "y=x"


If "y=x" , then:

"p=\\frac{\\partial z}{\\partial x}=1"

"z=x+\\phi(y)+c"


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