For any X and suitable p and q, solve y=Xpqz for z
*** Y=Xpq to the power z
If "q=\\frac{\\partial z}{\\partial y}=0" , then "y=x"
If "y=x" , then:
"p=\\frac{\\partial z}{\\partial x}=1"
"z=x+\\phi(y)+c"
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