Answer to Question #192857 in Differential Equations for Sourav Mondal

Question

dy/dx+2y/x=sinx/x²

Answer 1

$$x^2y'+2xy=\sin x$$

$$(x^2y)'=\sin x$$

$$x^2y=-\cos x+c_1$$

$$y=\dfrac{c_1}{x^2}-\dfrac{\cos x}{x^2}$$