Answer to Question #180228 in Differential Equations for Mr Eoghan O'Neill

Question

v=11sin4t-5cos5t

Answer 1

v=11sin4t-5cos5t

Differentiate w.r.t. t and we get-

$\dfrac{dv}{dt}=11\times 4cos4t+25sin 5t$

$\dfrac{dv}{dt}=44cos4t+25sin5t$