solve ( 3x y^3 + 2y )dx + (2x^2 y + x ) dy = 0
Given equation is-
"( 3x y^3 + 2y )dx + (2x^2 y + x ) dy = 0"
This equation is of the form Of exact differential equation-
"Mdx+Ndy=0"
So The solution of the equation is-
"\\dfrac{3y^3x^2}{2}+2yx+0=0"
"3y^3x^3+4yx=0"
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