Question

solve ( 3x y^3 + 2y )dx + (2x^2 y + x ) dy = 0

Answer 1

Given equation is-

$( 3x y^3 + 2y )dx + (2x^2 y + x ) dy = 0$

This equation is of the form Of exact differential equation-

$Mdx+Ndy=0$

So The solution of the equation is-

$\dfrac{3y^3x^2}{2}+2yx+0=0$

$3y^3x^3+4yx=0$