y= emx
5(dy/dx) = 2y
Given that
"y = e^{mx}"
We have that
"\\dfrac{dy}{dx} = me^{mx}"
Substituting into the equation, we have
"5me^{mx} = 2e^{mx}\\\\ 5me^{mx} -2e^{mx} = 0 \\\\ e^{mx}(5m-2) = 0"
Since "e^{mx} \\neq 0" , we have that
"5m-2 = 0\\\\ 5m=2\\\\ m = \\frac{2}{5} = 0.4"
Hence, "y = e^{0.4x}"
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